min [ T , min $integral dX$ root mean sq anom ( Princeton tmax ) ]
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[ 89.75 - min ( T , min $integral dX$ root mean sq anom { Princeton tmax } ) ] / 8.02116E+06
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Princeton[
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tmax
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89.75
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-89.75
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SOURCES .Princeton tmax ngridtable [T ]rmsaover X integral [X ]minover min
1000